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a circle passes through three points a b and c with the line segment AC as its diameter a line passing through a intersects the chord BC at Point D inside the circle if and a d a b and c a b are alpha and beta and the distance between the point a and midpoint of line segment DC is D proves that area of the circle is given expression so we have this circle and AC is one of the diameters so we have this diameter AC and then we have a point B and we construct this triangle ABC this triangle ABC with this angle B is 90 degrees and this is your Center say oh and we join B with o now through this point a line is drawn which intersects BC at this point d that says angle d a b and c a b are alpha and beta so angle d a b is Alpha and this whole angle it is beta and says distance of a with midpoint of line segment CD it is D so if we take this midpoint is M so this is equal to this then this distance is given as d basically we have to find radius of this circle now what well say is well say t