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I want to explain about construction and solving equations page 99 in Cambridge checkpoint line right sorry canvas checkpoint 8 for 27 so lets go to your question number 1 here so because the arriving here so 2y plus 3 here is a call to 20 because this is the properties of the rectangle so we can write like this 2y plus 3 so theres no lawyer ok quantity name so we expand this expressions we can to Y because 2 times y and then plus 2 times 3 we get 6 equal to to me okay 2x 2y the six goes to the right side say will be 20 minus 6 rights to Y so 2106 is tall so top equals 12 so we know that y equal to 12 over 2 36 all right very simple rights and then we get the value of y and then axis we are going to find the value of x so still the same way the upper one is the s equal to the below one so 5x minus 3 equal to 37 so 5x minus 3 goes to the right so become positive 37 plus 3 so 5 X to the 7 plus 3 equal to 40 then X equal to 40 over 5 equal to 8 so we get the value of x and y x equal to
