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for two the offset will integrate or evaluate this one so here we say 2 plus 1 over 2 plus 1 minus 2 x power 1 plus 1 over 1 plus c 1 minus c 3 x so what is happening here is that you check the power which is there so this is part two so you say power two plus one is this one and then the new power this new power divided okay so you divided all this all this thing by the new power minus here is power one so one plus one which is here one plus one divide it this one and then when you have a constant for this one this question when you have a constant you know you know that number you just put a zero but for integration when you have a constant apply the letter or the variable that you are respecting it with so in this case we are respecting with the x so we put x here so now we can clean it up on top of three over three because two plus one is three plus one here is three here two here we have two over two minus here three so now were here here this one do this one so im something li
