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click the Bell icon to get latest videos from Ekeeda Hello friends in this video we are going to see problem number two which is based on integration by substitution let us start evaluate integral X raise to n minus 1 into cos of X raise to n DX here also friends we know that integration of cos x raise to n is not possible for that we must substitute a part as t after that taking its derivative the remaining part must be converted in terms of DT we have two options that is X raise to n minus 1 and cos of X raise to n if I substitute X raise to n minus 1 St its derivative will be never X raised to it but if I substitute X raise to n St in its derivative part I will get the term X raise to n minus 1 let us see how to do that put X raise to n as T differentiating the above function with respect to T derivative of X raise to n will give you n into X raise to n minus 1 and with X you can directly write DX and on the right hand side you can directly write it as DT further we need to check a