Integrate formula transcript easily

Aug 6th, 2022
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How to Integrate formula transcript

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in this video were going to talk about how to use the special integration formulas to find the indefinite integral of trig substitution problems so lets use this problem as an example what is the integral of the square root of 25 minus 4x squared dx now you need to know which formula to use in order to find the answer and heres the formula that you need the antiderivative of the square root of a squared minus u squared d u this is equal to one half a squared arc sine u divided by a plus u square root a squared minus u squared plus c so what you need to do first is you need to determine the values of a and u you need to know what a and u are equal to so we can clearly see that 25 corresponds to a squared and 4x squared corresponds to u squared so we could say that a or a squared is 25 and u squared is 4x squared now if we take the square root of both sides we can get the value of a so a is a constant use the variable a is five and the square root of four x squared is two x now we ne

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Formula for Integration: \int e^x \;dx = e^x+C.
2:48 5:05 TRICK TO MEMORIZE INTEGRATION FORMULAS || HOW TO LEARN YouTube Start of suggested clip End of suggested clip You can easily write from integral of sine X DX integral of sine X DX is what - cos x so integral ofMoreYou can easily write from integral of sine X DX integral of sine X DX is what - cos x so integral of tan X DX.
0:04 3:12 Antiderivative of e^(-2x) | Integration of exp - YouTube YouTube Start of suggested clip End of suggested clip Of minus 2x. Let I be equal to integration of e to the power minus 2 X with respect to X to simplifyMoreOf minus 2x. Let I be equal to integration of e to the power minus 2 X with respect to X to simplify the integration. I have assumed minus 2x is equal to you taking differential of both sides.
Hence, the value of integration of e 2 x d x is 1 2 e 2 x + c .
Therefore, the anti derivative of e2x is 21e2x.
udvdx dx = uv vdu dx dx. This is the formula known as integration by parts.
Using this fact we conclude that the integral of e^3x is (e^3x)/3 + c where c is an arbitrary constant. The answer is e3xdx=e3x3 .
We will use the integration rule for ex : eudu=eu+C. So, for the given integral, let u=4x . This implies that du=4dx . e4xdx=14e4x4dx=14eudu=14eu+C.

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