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how can we find the indefinite integral of sine squared of x dx using the reduction formula for sine now heres the formula that you need to use the integral of sine raised to the n of x dx its negative one over n cosine x sine to the n minus one power of x plus n minus 1 over n times the integral of sine raised to the n minus 2 power of x dx so in this problem we can see that n is equal to two so using the formula its going to be negative one over n or negative one over two cosine x sine n minus one or two minus one which is one so we could simply say sine x plus n minus one over n so thats two minus one over two which is one over two integral sine n minus two so two minus two is zero anything raised to the zero power is one so this becomes one dx now the integral of one dx is simply x so we get this answer this is going to be one half x plus c now you can leave your answer like this or you can adjust it if you wish to adjust that you need to be familiar with the double angle form