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how about this integral just use a u-substitution and remember your natural logarithm rules this should work out okay but we can try a different way by splitting up this fraction and integrating like this we remember the antiderivative of 1 over X is natural log X the antiderivative of 1 over 1 then should be natural log of 1 and even combining them incorrectly with properties of logarithms to log of x plus one does in fact give us the correct answer