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GP sum is calculated by one of the following formulas: Sum of n terms of GP, Sn = a(1 - rn) / (1 - r), when r 1. Sum of infinite terms of GP, Sn = a / (1 - r), when |r| 1.
The condition for any three numbers to be in G.P is that the common ratios should be same between any two consecutive numbers.
The three numbers are 1,3,9. The sum of three numbers which form a geometric progression is 13 and the sum of their squares is 91. Find the numbers. Find three numbers which form a geometric progression if their sum is 35 and the sum of their squares is 525.
We suggest students to assume the geometric variables in the following manner: If we need to assume three numbers in G.P. then a/b, a, ab here common ratio is b. Four number in G.P. a/b3, a/b, ab, ab3 here common ratio is b. Five numbers in G.P. a/b2, a/b, a, ab, ab2 here common ratio is b.
The three numbers in G.P. are 3,6,12.

People also ask

Three positive numbers form an increasing G. P. If the middle term in the G. P. is doubled, the new numbers are in A. P. Then the common ratio of the G. P. is2 + sqrt{3}sqrt{2} + sqrt{3}3 + sqrt{2}2 - sqrt{3}
9, 3 , 1 are the numbers. Q. Three numbers are in GP, whose sum is 13 and the sum of whose squares is 91. Find the numbers.
2,4,8.

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