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To prepare a 0.5 M solution weight out 0.5 moles of glucose. One mole of glucose is 180 grams, so 0.5 moles of glucose would be 90 grams (180 g/mole X 0.5 mole = 90 g). Then, add water until you have 1 liter of solution (0.5 moles/liter).
A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.
Molar solutions To prepare a 1 M solution, slowly add 1 formula weight of compound to a clean 1-L volumetric flask half filled with distilled or deionized water. Allow the compound to dissolve completely, swirling the flask gently if necessary.
concentrations and amounts. So, if you dissolve 0.5 mol of a compound in one litre of solvent the concentration of the compound is 0.5 mol/l, or 0.5 M. 100ml of the solution contains 0.05 mol.
Answer and Explanation: In chemistry M stands for molarity, a measure of the concentration of a solution. Molarity is the number of moles solute in one liter of solvent. For example a solution that has 5 moles of sugar in one liter solution has a concentration of 5M, or 5 molar.
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2 molar solution means 2 M. given moles of solute = 0.5 mole.
A 1 molar (M) solution will contain 1.0 GMW of a substance dissolved in water to make 1 liter of final solution. Hence, a 1M solution of NaCl contains 58.44 g. Example: HCl is frequently used in enzyme histochemistry.
If you dissolve 58.44g of NaCl in a final volume of 1 litre, you have made a 1M NaCl solution. To make a 0.1M NaCl solution, you could weigh 5.844g of NaCl and dissolve it in 1 litre of water; OR 0.5844g of NaCl in 100mL of water (see animation below); OR make a 1:10 dilution of a 1M sample.
Case (III): When the density of the solvent is more than 1g/mL : This means that the volume of the solvent will be less than its mass. Under these circumstances , 1M solution will be more concentrated than 1m solution.
A mole is the amount (10) of material containing 6.02214 × 1023 particles.

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