Molarity worksheet 1 2025

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To prepare a 0.5 M solution weight out 0.5 moles of glucose. One mole of glucose is 180 grams, so 0.5 moles of glucose would be 90 grams (180 g/mole X 0.5 mole = 90 g). Then, add water until you have 1 liter of solution (0.5 moles/liter).
A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.
Molar solutions To prepare a 1 M solution, slowly add 1 formula weight of compound to a clean 1-L volumetric flask half filled with distilled or deionized water. Allow the compound to dissolve completely, swirling the flask gently if necessary.

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concentrations and amounts. So, if you dissolve 0.5 mol of a compound in one litre of solvent the concentration of the compound is 0.5 mol/l, or 0.5 M. 100ml of the solution contains 0.05 mol.
Answer and Explanation: In chemistry M stands for molarity, a measure of the concentration of a solution. Molarity is the number of moles solute in one liter of solvent. For example a solution that has 5 moles of sugar in one liter solution has a concentration of 5M, or 5 molar.
2 molar solution means 2 M. given moles of solute = 0.5 mole.
A 1 molar (M) solution will contain 1.0 GMW of a substance dissolved in water to make 1 liter of final solution. Hence, a 1M solution of NaCl contains 58.44 g. Example: HCl is frequently used in enzyme histochemistry.
If you dissolve 58.44g of NaCl in a final volume of 1 litre, you have made a 1M NaCl solution. To make a 0.1M NaCl solution, you could weigh 5.844g of NaCl and dissolve it in 1 litre of water; OR 0.5844g of NaCl in 100mL of water (see animation below); OR make a 1:10 dilution of a 1M sample.

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