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A compound contains 75% carbon and 25% hydrogen.... ElementsCarbonHydrogenAtomic mass (periodic table)121Number of moles = Amount in question Atomic mass75 12 =6.2525 1 =25Mole ratio (divide each number of moles by the smallest number of moles)6.25 6.25 =1Empirical formula CH4 25 6.25 = 4Empirical formulaCH41 more row
If the hydrocarbon has 80% carbon content, then the empirical formula is CH3 .
Therefore, empirical formula is C1H4 or simply, CH4 .
0:00 0:44 What is the Empirical Formula of N2O4 (Dinitrogen Tetraoxide) YouTube Start of suggested clip End of suggested clip So your empirical formula here is no2 done.MoreSo your empirical formula here is no2 done.
Let's find the Molar mass of Carbon=12. Molar mass of Hydrogen=1. Molar mass of Oxygen=16. Mass of CH2O=12+2(1)+16=30. Molecular weight of compound given is 180. So, the molecular weight is 30180=6. \u21d2 Molecular formula of compound is C6H12O6.

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A compound contains 75% carbon and 25% hydrogen.... ElementsCarbonHydrogenAtomic mass (periodic table)121Number of moles = Amount in question Atomic mass75 12 =6.2525 1 =25Mole ratio (divide each number of moles by the smallest number of moles)6.25 6.25 =1Empirical formula CH4 25 6.25 = 4Empirical formulaCH41 more row
So an organic compound that has a molar mass of 60 grams per mole and an empirical formula of CH2O has a molecular formula of C2H4O2.
A hydrocarbon is composed of 75% carbon.
Whereas CH2O is the empirical formula for glucose, C6H12O6 is the molecular formula. An actual molecule of glucose contains six carbon atoms, twelve hydrogen atoms, and six oxygen atoms. (Or six moles of carbon atoms, 12 moles of hydrogen atoms, and six moles of oxygen atoms).
Empirical formula of a compound is CH2O . Its molecular mass is 60 .

what is the empirical formula of a compound containing 75 0 of c and 25 0 of h