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another question if 2^ 5 x take 1 was equal to 3x then to solve this again I canamp;#39;t find any base that would be the same as two um or three in terms of base two those are the two lowest bases that I have so I take logs of both sides I take log to the base 10 of both sides now Iamp;#39;d bring the powers out the front so that would be 5 x take 1 log 2 is = X log 3 I multiply out this bracketed part here and so I get 5x * log 2 take 1 * log 2 is equal to X log 3 then I need to get all my uh Logs with xamp;#39;s in front of them all on one side and my Logs with non xamp;#39;s in front of them on the other side so if I bring this one over if itamp;#39;s plus X log 3 on this side when I bring it over it becomes take X log 3 and that is equal to if this is minus log2 on this side we going to bring it over here becomes plus log 2 moving up the top here I can now take a factor common factor of my uh side here I can take X out of both and so if I take X as a common factor out Iamp;#