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if you havent done so yet please pause the video and read the question why dont we go ahead and try to draw a picture based on the given information so weve drawn a line that passes through the point 3 comma 5 and encloses a triangular region off here in the first quadrant we can even color in the area of the triangle just to make it clearer now we know the general equation of a straight line looks like the following this happens to be the point-slope form for the equation of a line we can see from the picture and from the description that the line passes through the point 3 comma 5 so essentially we know one point on the line as x1 comma y1 so that means we can plug 3 4 x1 and 5 in for y1 into the equation of the line next we will mark off the x and y-intercepts of the line the x-intercept would be located right here of course and then the y-intercept is located over here the reason that those two intercepts are important is as follows we can see that the area enclosed as mentio