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all right thanks for watching and today i would like to tell you a neat little trick for evaluating three by three determinants for instance how do we calculate the determinant of two minus five three one seven minus two minus one four one well itamp;#39;s pretty simple you just repeat the first column and the second column so minus five seven four and then what you do you take the uh consider the diagonal terms and take the product so 2 times 7 times 1 thatamp;#39;s 14 and then continue that becomes minus 10 i believe and then 3 times 1 times 4 that is 12 and you take the sum which i believe gives you sweet 16. and then you consider the anti-diagonal terms so here i believe you get minus 21 4 times minus 2 times 2 thatamp;#39;s minus 16 and then 5 1 times 1 times minus 5 that is minus 5. and then you take the sum here which becomes minus 42 and then you have 16 and you have minus 42 so 16 minus minus 42 that gives you 58 which is the answer