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okay cool so now were going to look at we have a question about structural equivalence so here we have seven different types and were going to talk about how to decide which ones are structurally equivalent okay so the easy way to do this is we make a table of types 1 0 1 2 3 4 5 6 0 1 2 3 4 a bunch of Mines okay great okay so first so we assume that everything is structured equivalent right so thats what we did at the start so soon everything structured equivalent and we go through and were going to try and prove that things are not truffle equal 1 so 0 0 we know definitely structure like 1 0 1 are they structurally equivalent nope yeah ones an int 1 the string beans can be string so theyre two basic types so the two basic types arent roughly equivalent theyre not different its not the same basic type theyre not sure shuffling ok 0 and T 2 why pointer exactly yeah 0 T 3 nope 0 2 4 5 6 we can kind of use what I talked about today so these are all structs so theres no way
