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In this tutorial, the presenter discusses solving the LeetCode problem 203, which involves removing all occurrences of a specified value from a linked list. Using the example linked list [1, 2, 6, 3, 4, 5, 6], the goal is to remove all elements with the value 6. The solution involves checking each element: if it matches the value to be removed, it is discarded; otherwise, it remains. The tutorial emphasizes using multiple pointers to iterate through the list, update pointers, and ensure that the new head of the list is returned correctly, even if the element to be removed is the head of the list itself.