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okay my equation is if x + 1 is a factor of f of X equals 8x to the third plus KX squared minus 4x minus 2 then fine k and if x + 1 is a factor of this equation then we know that negative 1 is a zero because negative one plus one equals zero and then that would be a solution to ax in this equation so then weamp;#39;re going to plug negative one in so itamp;#39;s going to be f of x equals 8 times negative 1 to the third plus K times negative 1 squared minus 4 times negative 1 minus 2 and now we just need to further solve it so itamp;#39;s going to be f of x equals eight times um negative one because negative 1 to the third is just a negative one plus um k times one because negative one squared is just positive one and then this is going to be minus a negative 4 minus 2 because the negative one makes before negative and then weamp;#39;re going to further simplify it to negative 8 plus k plus 4 minus 2 and now weamp;#39;re going to set this equal to zero to find um what f of what the
