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a circular coil of radius 10 cm is placed in magnetic field such that outward unit Vector normal to the surface of coil is this the magnetic flux linked with the coil what is the formula of magnetic flux it is dot product of magnetic field and area Vector magnetic field given 1 I plus5 JC area vector magnitude into Direction B Vector a into n cap where a is magnitude of area and N capap is the direction of the area Vector what is magnitude of the area the area of the circular coil which is PK r 3.14 10 upon 100 into 10 upon 100 to convert into meter and N capap value 6 I +8 jcap note one more thing the magnetic field is in mesla 10us now solving this take dot product of these two vectors 1 into 6 is 6 and 0.5 into point8 is4 so 0.6 + 0.4 into this is 3.14 this will be 10^ - 5 this is 1 3.14 into 10us 5 Weber this is the SI unit of flux Weber option match if I take it on this point on the right hand side 31.4 into- 6 Weber 31.4 this is 31.4 micro so answer is C part