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how many different alkenes are formed when two bromo2 methyl butane reacts with ethanolic potassium hydroxide well here is our halogenoalkane and under these conditions the hydroxide ion is going to act as a base and remove a hydrogen from one of the carbon atoms adjacent to the halogen containing carbon atom in an elimination reaction and so we could remove a hydrogen atom from the right hand side along with the bromine and if we do that we make an alkene that we call two methyl Bute two in if we remove a hydrogen atom from the left hand side along with the bromine we end up making two methyl butes one in if we remove a hydrogen atom from the methyl group we actually end up making the same alkene again to methyl Bute one in and so you can see actually we can only make two different alkenes and so a is the correct answer
