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Welcome! In this tutorial, we will solve this maximization problem using graphical method. Lets label the constraints C1 to C4 for reference purposes. Lets start by setting up tables to find the points. The line equation for Constraint 1) is 7X - Y =3 So when X = 0, Y = -3 And when Y = 0, X = 0.43 These two points are not that useful to us because the first has a negative which will take us far away from the feasible region and make the graph very small. The other has a fractional value that cannot be easily located on the graph. So lets try finding more points. To make it easy to find useful points, it is better to rewrite the equation in terms of one variable. In this case, we can write it in terms of Y. That is, Y = 7X - 3. We can now use trial and error to find better points. For example, when X = 0.5, Y also equals 0.5. And when X = 1, Y equals 4. For Constraint 2) we have the line -3x + 6y = 10 when X = 0, Y = 1.67. And when Y = 0, X = -3.33. Again, lets try more points. Rewr