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let us discuss caught the joining two points t1 t2 on the parabola Y square equal to 4x now if you take the parabola like this Y square equal to 4x as we discussed earlier any point can be taken as dat 180 square comma 280 particularly we require two points means to distinguish between these two points let us say this is t1 and this is t2 so this point will become yet even Square come out to it even and this is a t2 square comma 282 now we require the equation of line joining of these two points once you know the two points from straight line chapter two points form you can apply now first given parabola is y square equal to 48 let us consider equation 1 P 81 Square come out to 81 q 82 Square come out to 82 or two points on one now we require equation of PQ so equation of chord joining called joining PQ otherwise you can write t1 t2 also joining T 1 comma T 2 is y minus let us take the first point y -2 e 81 is equal to now the formula Y minus y1 equal to difference of XY coordinates b
