Time is a vital resource that each enterprise treasures and attempts to transform into a gain. When picking document management software, take note of a clutterless and user-friendly interface that empowers customers. DocHub offers cutting-edge tools to maximize your file managing and transforms your PDF editing into a matter of one click. Insert Calculations into the Letter Of Continuing Guarantee (Unlimited Amount) with DocHub to save a lot of efforts and increase your efficiency.
Make PDF editing an simple and easy intuitive process that will save you plenty of valuable time. Effortlessly change your files and send out them for signing without the need of switching to third-party software. Give attention to pertinent tasks and improve your file managing with DocHub today.
Here were given a linear first order differential equation with the initial condition y of negative two equals negative one. Were asked to find the interval in which the solution of the initial value problem above is certain to exist. So looking at our notes below, if we have a linear first order differential equation written in this form here with this initial condition if p of t and f of t are both continuous on an open interval from a to b, then there exists a unique solution for every t on the interval. And if we find all the intervals for which both p of t and f of t are continuous this is called the interval of validity. And if the interval contains t sub zero, which is the input value of the initial condition, then there exists a unique solution on the interval that satisfies the initial value problem. So to answer this question, well first find the interval of validity whichll be the intervals to which both p of t and f of t are continuous, and then well find the interval