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- NASA LAUNCHES A ROCKET AT T = 0 SECONDS. ITS HEIGHT IN METERS ABOVE SEA LEVEL AS A FUNCTION OF TIME IS GIVEN BY THE FUNCTION H OF T. WE WILL ASSUME THE ROCKET WILL SPLASH DOWN INTO THE OCEAN. WE WANT TO ANSWER TWO QUESTIONS. 1. WHAT TIME WILL THE ROCKET SPLASH INTO THE OCEAN? 2. HOW HIGH ABOVE SEA LEVEL WILL THE ROCKET docHub? NOW, WE JUST SOLVED THIS PROBLEM USING A GRAPHING CALCULATOR, BUT NOW WERE GOING TO SOLVE IT USING WHAT WE KNOW ABOUT QUADRATIC FUNCTIONS AND QUADRATIC EQUATIONS. SO BEFORE WE SOLVE THIS I THINK ITS GOING TO BE HELPFUL TO UNDERSTAND WHATS HAPPENING IF WE GRAPH THIS FUNCTION. SO IVE ALREADY GRAPHED THIS USING SOME GRAPHING SOFTWARE. SO OUR X AXIS REPRESENTS TIME IN SECONDS AND OUR Y AXIS REPRESENTS THE METERS ABOVE SEA LEVEL. NOTICE AT TIME T = 0 THE ROCKET WOULD BE RIGHT HERE, WHICH WOULD BE THE Y INTERCEPT. THIS REPRESENTS THE INITIAL HEIGHT OF THE ROCKET AND THEN AS TIME PASSES THE ROCKET GOES UP, docHubES A MAXIMUM HEIGHT HERE AT THE
