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hello everyone today we are going to find the shape factor for a triangular section let us consider a triangle having the height h and breadth b we know the formula for the shape factor is equal to zp by set in this formula set p is the plastic modulus set is the elastic modulus first let us calculate elastic modulus the formula is i by y we know that for a triangle the moment of inertia formula is bh cube by 36 this triangle is not symmetrical in this triangle the centroid lies at a distance of 2h by 3 from the apex and at a distance of h by 3 from the base the neutral axis lies along the centroid from the neutral axis we are having two different values one is two h by three and another is h by three so here we may have some confusion which one we have to apply for y for the value of y we have to take the maximum value comparing both of these values 2h by 3 is the maximum value so y max is equal to 2h by 3 in the formula we can apply the values of i and y we can take 2h by 3 inversely