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weamp;#39;re going to condense this using properties of logarithms so log a minus log B can be written as log A over B so weamp;#39;re going to write this as the log of a quotient and then set it equal to one and now weamp;#39;re going to do 10 to the power both sides and 10 to the power log something since the base is 10 itamp;#39;s going to be that thing so X over x minus 1 equals 10 to the first Power which is 10 and then if we cross multiply we get x equals 10x minus 10 put the Xamp;#39;s together 9x equals 10 and x equals 10 9. we obviously need to make sure our solution works in the original equation and it actually does
