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Hey guys, in this video Im going to do thisstatistics and probability problem. It says suppose that Y has pdf the following and then it gives me a function thats defined from 0 to 1 as ky times 1 minus y and 0 elsewhere. Then it says find the value of k that makes f(y) a probability density function. So were given a function and we want to determine what constant k will make this function f(y) a pdf. To be defined as a probability density function, there have to be two conditions that are met. For a function to be a pdf f(y) has to be greater than or equal to 0 for all y. So y defined from negative infinity to infinity has to be positive, so greater than or equal to zero. Thats the first condition. And then the second condition is that from negative infinity to infinity f(y) dy has to be equal to one. So if you integrate over the entire function, that area under the curve of your function has to be equal to one. Lets go ahead and check these two assumption