Delete city in binary smoothly

Aug 6th, 2022
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How to Delete city in binary

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In this lesson, were going to write code to delete a node from binary search tree. In most data structures deletion is tricky. In case of binary search trees too, its not so straightforward. So lets first see what all complications we may have while trying to delete a node from binary search tree. I have drawn a binary search tree of integers here. As we know in a binary search tree for each node value of all nodes in its left subtree is lesser and value of all nodes right subtree is greater. For example, in this tree if Ill pick this node with value 5 then we have 3 and 1 in its left subtree which are lesser and we have 7 and 9 in its right subtree which are greater, and you can pick any other node in the tree and this property will be true else the tree is not a BST. Now when we need to delete a node, this property must be conserved. Lets try to delete some nodes from this example tree and see if we can rearrange these things and conserve the property of binary search tree or n

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Approach: Recursion Compare the value of key with the value of root. If the key root - value, recursively traverse the right subtree. If key root - value, recursively traverse the left subtree. While traversing if key == root-value, we need to delete this node: If the node is a leaf, make root = NULL. Return root.
Algorithm Create a new BST node and assign values to it. insert(node, key) i) If root == NULL, return the new node to the calling function. ii) if root=data key. call the insert function with root=right and assign the return value in root=right. Finally, return the original root pointer to the calling function.
Algorithm Create a new BST node and assign values to it. insert(node, key) i) If root == NULL, return the new node to the calling function. ii) if root=data key. call the insert function with root=right and assign the return value in root=right. Finally, return the original root pointer to the calling function.
BST Removing Element Recursively If no children - Just delete. If a single child - Copy that child to the node. If two children - Determine the next highest element (inorder successor) in the right subtree. Replace the node to be removed with the inorder successor. Delete the inorder successor duplicate.
Insertion in Binary Search tree To insert an element in BST, we have to start searching from the root node; if the node to be inserted is less than the root node, then search for an empty location in the left subtree. Else, search for the empty location in the right subtree and insert the data.
To delete a node in a BST: Find the node to be deleted.Once we find that the root is the key, identify the case: Root is the leaf (no child): delete it. Root has one child: Replace the root with the child. Root has both children: Replace it with successor/predecessor and delete it using recursion.
When we delete a node, three possibilities arise. 1) Node to be deleted is the leaf: Simply remove it from the tree. 2) Node to be deleted has only one child: Copy the child to the node and delete the child. 3) Node to be deleted has two children: Find inorder successor of the node.
Delete function is used to delete the specified node from a binary search tree.Function: void deletion(Node* root, int item) { Node* parent = NULL; Node* cur = root; search(cur, item, parent); if (cur == NULL) return; if (cur-left == NULL cur-right == NULL)

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