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so here weamp;#39;re given a list of nuclides and the type of nuclear Decay that they undergo and what weamp;#39;re asked to do is balance the nuclear reactions weamp;#39;re going to do this by paying close attention to both the mass number a and the atomic number Z for each of these starting materials so first we have uranium 234 which is undergoing alpha decay we know that alpha decay produces a helium nucleus so the only other thing that we need to do to balance both sides of this equation is subtract the two protons from the number of protons on uranium to leave us with 90 and subtract the drop in mass number of four for the total helium nucleus from the 234 of the original uh uranium to get 230 an atomic number of 90 corresponds to thorium if we look at Part B now weamp;#39;re going to basically take that same thorium nuide and do the same process so weamp;#39;re going to kick out a helium nucleus subtract two from the atomic number and subtract four from the mass number and
