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hello friend this topic is why copy constructor takes argument as reference you might have seen that all the time but you might not be knowing that we will try to understand lets look at the code now so this is the good and this is one cool class here and this is a default computer and this is a copy comes over here so I have a table from object Here I am setting the value 10 so is getting test set here now we are creating another object called f2 this statement the Copic inspector will be called and this is the synthetic reagent movie right four copies effective this constant is for you wont accidentally change this object whatever you are passing because you are in bit intended to pass this into this you are not ended intended to change anything inside this object ok so you are taking this as the constant and the second question is you are taking this as a reference just because you dont want to make a recursive loop inside because exit you have not used this so what does it look
