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This is a 50/50 beam splitter. When two photons enter, there are 4 possible outcomes. One Two photons enter and both exit on the left side Two The photons enter and both exit on the right side Three Both photons exit on the same side at which they entered. Four Both photons cross over to the opposite side to the one at which they entered. In general the state at the output of the beam splitter will be a superposition with contributions from each of these four options. The contribution to the final state from both photons crossing to the opposite side of the beam splitter has opposite sign to the contribution from both photons staying on the same side. If the two photons have identical wavepacket shapes so that they are indistinguishable from each other then the contributions have exactly equal amplitude. However, because they have opposite sign, they cancel out. So, the two paths which could result in one photon