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everyone welcome back and letamp;#39;s write some more neat code today so today letamp;#39;s solve the problem flatten binary tree into a linked list we are given the root of a binary tree and we want to flatten it so that it turns into a linked list not necessarily a true linked list because you know this data structure obviously is made up of tree nodes binary tree nodes where each node has two pointers a left pointer and a right pointer but they want us to condense it into a linked list where weamp;#39;re not really making use of the left pointer right for each left pointer of each node itamp;#39;s just pointing at null the right pointer is what weamp;#39;re actually going to be using which is going to assemble all of these nodes into a linked list so this isnamp;#39;t too difficult to do but there is a catch the ordering of the linked list should be the same as the pre-order traversal of the binary tree now this isnamp;#39;t as bad as it sounds this is actually going to make
