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thank you we need to find the derivative of f of x equal to 2 times 1 minus x squared plus nine times one minus X plus six if we let U equal to 1 minus X its derivative U Prime will be zero and then the derivative of negative X will be negative one now f as a function of U can be written as two times U squared which will become passive of the form U to the N Prime for its derivative equal to n times U to the N minus 1 times U Prime plus 9 times U plus six F Prime of U itamp;#39;s derivative will be we keep the coefficient two and then the derivative of U squared will be two times U to the 2 minus one times U Prime chain rule the derivative of 9u is nine times U Prime and the derivative of six is zero 2 times 2 is equal to 4 and when we substitute U is one minus X and U Prime is negative 1 plus 9 times U Prime which is negative one four times negative 1 is negative four negative four times one minus x minus nine nine times negative one so the correct tensor is C we looking for