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now how do we evaluate the cost of the sort merge join well we are going to sort r sort s and then we will scan r and s and merge them in memory so the cost is basically the cost of sorting r plus this cost of sorting s plus the cost of scanning r and s in the worst case actually all of the joint values of r and all of the joint values of s are exactly the same in that case the output is the cross product of all the tuples in r and s because everything matches so in that case it degenerates into a nested loop joint with cost of vertical bar r times bracket s which is actually lower than the cost of the sort merge joint but thats extremely unlikely and its the kind of thing that a good optimizer would keep an eye out for and avoid so we can usually assume that in a sort merged joint theres plenty of distinct values in the joint columns and those little mini cross products where we take multiple join keys on r multiplied to the same joint key on s and we form all pairs that only happe
