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hi in this video I will demonstrate an example of a how to find a cut-off score weamp;#39;re given an example it states the following the LSAT law school admission test has an average score of around 152. the standard deviation is around 15. find the minimum score needed to be in the upper 10 percent of LSAT scores round the final answer to the nearest whole number assume the distribution is normal and thatamp;#39;s a key phrase because that allows us to use the normal distribution so we draw the normal distribution label the key elements the mean is 152 standard deviation is 15 and weamp;#39;re given the upper 10 percent so thatamp;#39;s represented by this area here 0.10 X is the cutoff score thatamp;#39;s the value we have to find now to find the value we need to determine the corresponding Z value so in order to find this Z value we need to compute 1 minus 0.10.9 we look up the area closest to 0.9 in table e thatamp;#39;s going to be 0.8997 looking to the left 1.2 looking up