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hey everyone welcome back to take you forward today we will be solving uh the 23rd problem from the dynamic programming playlist and the problem goes as unbounded knapsack so what is the problem state by the way in order to understand this question you should have seen the problem zero one knapsack which is the dp 19 so please make sure you watch zero one knapsack okay so how is unbounded knapsack different from the zero one knapsack so over here there is a thief right who goes into the house with a bag weight of 10 okay and there are items first item has a weight of two and if he steals that item he gets a value five the second item has a weight of four and if he steals that he gets a value eleven the third item has a weight of six if he steals that he gets a weight off he gets a value of 13 but the difference from like how is this problem different from zero one knapsack lets understand this so in zero one knapsack it was clearly stated that there will only be one occurrences i rep